you mix two different brands of cranberry juice. one brand of juice is 50% juice. the other brand is 80% juice. the outcome is 5 liters of 60% juice. How many liters of both 50% juice and 80% juice are used?
ok, there are five liters total at the end. suppose we use 'x' liters of the 50% type of juice; that means we are using (5-x) liters of the 80% type of juice since again, we use 5 liters total.
To set up an equation, we use:
(Amount of Juice from 50% brand) + (Amount of Juice from 80% brand)
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you mix two different brands of cranberry juice. one brand of juice is 50% juice. the other brand is 80% juice. the outcome is 5 liters of 60% juice. How many liters of both 50% juice and 80% juice are used?
ok, there are five liters total at the end.
suppose we use 'x' liters of the 50% type of juice; that means we are using (5-x) liters of the 80% type of juice since again, we use 5 liters total.
To set up an equation, we use:
(Amount of Juice from 50% brand)
+
(Amount of Juice from 80% brand)
=
total amount of juice.
the equation you would get would be:
.5(x) +.8(5-x) = .6(5)
solving, u get
.5x + 4 - .8x = 3
-.3x = -1
x = 1/.3
x = 10/3
x = 3 1/3 liters
of the 50% kind of juice and
1 2/3 of the 80% kind!!!
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